For a given reaction, ΔrH = +35.5 kJ mol-1 and ΔrS = +83.6 J K-1 mol-1....

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For a given reaction, ΔrH = +35.5 kJ mol-1 and ΔrS = +83.6 J K-1 mol-1....

For a given reaction, Δ_rH = +35.5 kJ mol^-1 and Δ_rS = +83.6 J K^-1 mol^-1. The reaction is spontaneous ________. Assume that Δ_rH and Δ_rS do not vary with temperature.

A. at all temperatures

B. at T < 298 K

C. at T < 425 K

D. at T > 425 K

E. at T > 298 K

science chemistry

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For a given reaction, ΔrH = +35.5 kJ mol-1 and ΔrS = +83.6 J K-1 mol-1....

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For a given reaction, ΔrH = +35.5 kJ mol-1 and ΔrS = +83.6 J K-1 mol-1....

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For a given reaction, ΔrH = +35.5 kJ mol-1 and ΔrS = +83.6 J K-1 mol-1....

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For a given reaction, ΔrH = +35.5 kJ mol-1 and ΔrS = +83.6 J K-1 mol-1....