Question

I need to write a program based on two finished programs (listm.py and setunion.py) to implement the intersection operation between two sets of list. The program should not use the Python built-in list and set related functions and operations.

I'm sorry about the program format is wrong(no "TAB" space), here is the same question I posted 2 days ago, but the question title is incorrect, there have complete images of my 3 Python program. The link is:

https://www.chegg.com/homework-help/questions-and-answers/need-write-program-based-two-finished-programs-listmpy-setunionpy-implement-intersection-o-q44800953?trackid=uNY0ilRc

Thank you!

here is listm.py

class List: def __init__(self, extlist=None): if extlist is None: self.inlist = [] else: self.inlist = extlist def length(L): return len(L.inlist) def isempty(L): if len(L.inlist)==0: return True else: return False def get(L, i): if isempty(L): print("The get() is unsuccessful!") print("The list is empty!") return -1 elif (i<1) or (i>length(L)): print("The get() is unsuccessful!") print("The index given is out of range!") return -1 else: return(L.inlist[i-1]) def locatebyvalue(L, x): position = 1 for item in L.inlist: if x == item: return position else: position = position+1 return -1 def locatebyid(L, idd): position = 1 for item in L.inlist: if item.id == idd: return position else: position = position+1 return -1 def insert(L, i, x): if (i<1) or (i>length(L)+1): print("The insert() is unsuccessful!") print("The index given is out of range!")    else: L.inlist.insert(i-1, x) def delete(L, i): if isempty(L): print("The delete() is unsuccessful!") print("The list is empty!") return elif (i<1) or (i>length(L)): print("The delete() is unsuccessful!") print("The index given is out of range!") return else: del L.inlist[i-1] def display(L): print(L.inlist)

here is setunion.py

from listm import * def un(setA, setB): n = length(setA) for i in range(length(setB)): x = get(setB, i+1) k = locatebyvalue(setA, x) if (k==-1): insert(setA, n+1, x) n = n+1 setA = List([1, 2, 3, 4, 5]) setB = List([2, 4, 5, 10, 11]) display(setA) display(setB) un(setA, setB) print("The union result is as follows") display(setA)

I'm trying to finish it by modify setunion.py and open a new file called intersection.py:

intersection.py

def intersection(seta,setb): setc=[] for num in seta: if num in setb: setc.append(num) return setc

And I add:

from intersection import * #on the top of setunion.py

print("The intersection is:") #below the setunion.py
print(intersection(setA,setB))

but finally I get the result is: TypeError: 'List' object is not iterable

What's wrong with me?

Answer 1

ANSWER:-

CODE:-

listm.py:-

class List:
    def __init__(self, extlist=None):
        if extlist is None:
            self.inlist = []
        else:
            self.inlist = extlist

    def length(L):
        return len(L.inlist)

    def isempty(L):
        if len(L.inlist)==0:
            return True
        else:
            return False
    def get(L, i):
        if L.isempty():
            print("The get() is unsuccessful!")
            print("The list is empty!")
            return -1
        elif (i<1) or (i>L.length()):
            print("The get() is unsuccessful!")
            print("The index given is out of range!")
            return -1
        else:
            return(L.inlist[i-1])
    def locatebyvalue(L, x):
        position = 1
        for item in L.inlist:
            if x == item:
                return position
            else:
                position = position+1
        return -1
    def display(L):
        print(L.inlist)
    def locatebyid(L, idd):
        position = 1
        for item in L.inlist:
            if item.id == idd:
                return position
            else:
                position = position+1
        return -1

    def insert(L, i, x):
        if (i<1) or (i>L.length()+1):
            print("The insert() is unsuccessful!")
            print("The index given is out of range!")
            
        else:
            L.inlist.insert(i-1, x)

    def delete(L, i):
        if L.isempty():
            print("The delete() is unsuccessful!")
            print("The list is empty!")
            return
        elif (i<1) or (i>L.length()):
            print("The delete() is unsuccessful!")
            print("The index given is out of range!")
            return
        else:
            del L.inlist[i-1]

setunion.py:-

from listm import *

def un(setA, setB):
    n = setA.length()
    for i in range(setB.length()):
        x = setB.get(i+1)
        k = setA.locatebyvalue(x)
        if (k==-1):
            setA.insert(n+1, x)
            n = n+1

setA = List([1, 2, 3, 4, 5])
setB = List([2, 4, 5, 10, 11])

setA.display()
setB.display()
un(setA, setB)
print("The union result is as follows")
setA.display()

setintersection.py:-

from listm import *
def intersection(seta,setb):
    setC= List()
    n = 0
    for i in range(setA.length()):
        x = setA.get(i+1)
        k = setB.locatebyvalue(x)
        if (k>-1):
            setC.insert(n+1, x)
            n = n+1
    return setC

setA = List([1, 2, 3, 4, 5,6,10])
setB = List([2, 4, 5, 10, 11])

setA.display()
setB.display()
setC = intersection(setA, setB)
print("The intersection result is as follows")
setC.display()

NOTE:- To access members in a class, first we need to create an object for that class, then we can access by using that object with '.' operator. The reason for getting error is setA and setB are List objects created by you.

we can not iterate through those objects. we didn't define any function in List class to iterate through list elements.

        If you have any doubts, please comment below. Please give positive rating.THUMBS UP.

          THANK YOU!!!

OUTPUT:-

setintersection.py

setunion.py

We were unable to transcribe this image

from listm import * def un(seta, setB): n = seta.length() for i in range (sets.length()): x = sets.get (i+1) k = seta.locatebyvalue (x) if (k==-1): setA.insert (n+1, x) n = n+1 seta = List([1, 2, 3, 4, 5]) setB = List([2, 4, 5, 10, 11]) setA.display ( ) setB.display ( ) un (seta, setB) print("The union result is as follows") setA.display ( ) Python 3.7.1 Shell File Edit Shell Debug Options Window Help Python 3.7.1 (v3.7.1:260ec2c36a, Oct 20 2018, 14:57:15) [MSC v.1915 64 bi 4)] on win32 Type "help", "copyright", "credits" or "license ()" for more information. >>> ============= RESTART: C:/Users/Bhanu Logan/Desktop/setunion.py ========= [1, 2, 3, 4, 5] [2, 4, 5, 10, 11] The union result is as follows [1, 2, 3, 4, 5, 10, 11] >>> |