Question

What is the freezing point of a 1.195 m aqueous solution of aluminum nitrate, Al(NO3)3? The Kf of water is 1.86°C/m. Give your answer in degrees C

Answer 1

Al(NO3)3 -------------> Al⁺³ + 3NO3^-

total 4 ions releasing so i = 4

Tf = i x Kf x m

m = 1.195

Kf = 1.86 ⁰c/m

Tf = 4 x 1.86 x 1.195

Tf = 8.89

Tf = 0 - 8.89

Tf = - 8.89⁰C

Answer 2

Al(NO3)3 -------------> Al⁺³ + 3NO3^-

total 4 ions releasing so i = 4

Tf = i x Kf x m

m = 1.195

Kf = 1.86 ⁰c/m

Tf = 4 x 1.86 x 1.195

Tf = 8.89

Tf = 0 - 8.89

Tf = - 8.89⁰C