A thin hoop (I = MR2) of mass 0.33 kg and radius 0.088 m rolls, without...
A 1.2 m radius cylinder with a mass of 8.8 kg rolls without slipping down a hill which is 5.7 meters high. At the bottom of the hill, what percentage of its total kinetic energy is invested in rotational kinetic energy?
A solid sphere (I = 2/5 MR2) of mass 0.44 kg and radius 0.022 m rolls, without slipping, down an incline of height 0.98 m. What is the speed of the sphere at the bottom of the incline?
A hoop with mass, M, and radius, R, rolls along a level surface without slipping with a linear speed, v. What is the ratio of rotational to linear kinetic energy? (For a hoop, I = MR2.)
A 1.9 m radius cylinder with a mass of 531.1 kg rolls without slipping down a hill which is 56.5 meters high. At the bottom of the hill, what fraction of its total kinetic energy is invested in rotational kinetic energy?
A 1.2 m radius cylinder with a mass of 5.9 kg rolls without slipping down a hill which is 8.2 meters high. At the bottom of the hill, what fraction of its total kinetic energy is invested in rotational kinetic energy?
A thin hoop of radius r = 0.82 m and mass M = 7.3 kg rolls without slipping across a horizontal floor with a velocity v = 1.1 m/s. It then rolls up an incline with an angle of inclination theta = 44 degrees. a) What is the maximum height h reached by the hoop before rolling back down the incline? b) Now, suppose a uniform solid sphere is used instead of a hoop. Use the same values of r,...
A hoop of mass M = 3 kg and radius R = 0.4 m rolls without slipping down a hill, as shown in the figure. The lack of slipping means that when the center of mass of the hoop has speed v, the tangential speed of the hoop relative to the center of mass is also equal to vCM, since in that case the instantaneous speed is zero for the part of the hoop that is in contact with the...
A hoop of radius 0.50 m and a mass of 0.020 kg is released from rest and allowed to roll down to the bottom of an inclined plane. The hoop rolls down the incline dropping a vertical distance of 3.0 m. Assume that the hoop rolls without slipping. (a) Determine the total kinetic energy at the bottom of the incline. (b) How fast is the hoop moving at the bottom of the incline?
Rolling Motion Up and Down an Incline (a) A rolling (without slipping) hoop with a radius of 0.10 m and a mass of 1.80 kg climbs an incline. At the bottom of the incline, the speed of the hoop's center-of-mass is v. = 7.00 m/s. The incline angle is NOT needed in this problem. Vf=0 Max h What is the angular speed of the hoop's rotation? Enter a number rad/s Submit (5 attempts remaining) What is the hoop's translational kinetic...
A hoop of mass M = 2 kg and radius R = 0.4 m rolls without slipping down a hill, as shown in the figure. The lack of slipping means that when the center of mass of the hoop has speed v, the tangential speed of the hoop relative to the center of mass is also equal to VCM, since in that case the instantaneous speed is zero for the part of the hoop that is in contact with the...