The mean length of shafts produced on a lathe has historically been 50 inches, with a standard deviation of 0.12 inch. If a sample of 50 shafts is taken, what is the probability that the sample mean would be greater than 50.04 inches?
z = 
z =
(50.04-50)/(0.12/
)
z = 0.023
A z-table and standard normal distribution curve can be used to find the probability that the sample mean would be greater than 50.04 inches. The results show that the probability is 4.92%
The mean length of shafts produced on a lathe has historically been 50 inches, with a...
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