When converting a base-N integer an-1an-2...a1a0 to decimal, the formula an-1×Nn-1 + an-2×Nn-2 + ... +...

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When converting a base-N integer an-1an-2...a1a0 to decimal, the formula an-1×Nn-1 + an-2×Nn-2 + ... +...

When converting a base-N integer a_n-1a_n-2...a₁a₀ to decimal, the formula a_n-1×N^n-1 + a_n-2×N^n-2 + ... + a₁×N¹ + a₁×N⁰ is used. Given a base-3 integer 22100222, what is the value of a_m×N^m for m being 2?

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Answer 1

Answer #1

a_n-1×N^n-1 + a_n-2×N^n-2 + ... + a₁×N¹ + a0×N⁰

m = 2

In 22100222

a0 = 2

a1 = 2

a2 = 2

m = 2

N^m = 2² = 4

a_m×N^m = a₂×N² = 2 x 4 = 8

Answer = 8

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Answer 2

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When converting a base-N integer an-1an-2...a1a0 to decimal, the formula an-1×Nn-1 + an-2×Nn-2 + ... +...

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When converting a base-N integer an-1an-2...a1a0 to decimal, the formula an-1×Nn-1 + an-2×Nn-2 + ... +...

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Add Answer to: When converting a base-N integer an-1an-2...a1a0 to decimal, the formula an-1×Nn-1 + an-2×Nn-2 + ... +...

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