Question

exchange rate = {'0.0045': 3, '0.0160': 2, '-0.0028': 6, '-0.0157': 1, '-0.0443': 1, '-0.0232': 1, '-0.0065': 9, '-0.0080': 12, '0.0052': 1, '-0.0052': 3, '-0.0283': 1, '-0.0087': 1, '-0.0020': 9, '-0.0290': 2, '0.0180': 3, '0.0030': 15, '-0.0170': 2, '0.0000': 63, '-0.0185': 3, '-0.0055': 5, '0.0148': 1, '-0.0053': 1, '0.0265': 1, '0.0010': 22, '-0.0015': 5, '0.0137': 1, '-0.0137': 2, '-0.0023': 2, '0.0008': 10, '0.0055': 6, '-0.0025': 6, '-0.0125': 2, '0.0040': 14, '0.0260': 1, '0.0070': 8, '0.0210': 1, '-0.0070': 8, '0.0395': 1, '-0.0040': 14, '-0.0255': 2, '0.0037': 3, '0.0060': 7, '0.0025': 7, '0.0095': 2, '-0.0100': 2, '-0.0085': 6, '-0.0248': 1, '0.0028': 8, '-0.0005': 7, '-0.0113': 1, '0.0418': 1, '-0.0075': 4, '0.0130': 4, '-0.0165': 1, '0.0020': 16, '-0.0090': 7, '0.0190': 4, '-0.0245': 1, '0.0240': 2, '-0.0225': 1, '-0.0230': 1, '-0.0295': 1, '-0.0330': 1, '-0.0139': 1, '0.0104': 1, '0.0032': 7, '-0.0117': 1, '-0.0035': 8, '-0.0010': 18, '0.0285': 1, '0.0012': 7, '-0.0202': 1, '-0.0098': 1, '0.0195': 1, '0.0075': 3, '0.0015': 8, '0.0005': 5, '-0.0130': 4, '0.0115': 1, '0.0245': 2, '0.0175': 1, '0.0155': 1, '0.0120': 3, '0.0185': 1, '-0.0078': 3, '0.0023': 2, '0.0340': 1, '-0.0105': 5, '0.0140': 2, '-0.0060': 9, '0.0125': 3, '0.0262': 1, '0.0143': 1, '-0.0120': 3, '-0.0380': 1, '-0.0095': 4, '0.0135': 2, '-0.0045': 6, '0.0100': 8, '0.0145': 2, '-0.0140': 6, '-0.0200': 1, '-0.0030': 11, '0.0035': 6, '-0.0175': 1, '0.0105': 3, '0.0080': 10, '0.0165': 3, '0.0050': 16, '0.0230': 1, '-0.0050': 3, '0.0170': 2, '-0.0110': 2, '-0.0115': 3, '0.0255': 1, '0.0300': 1, '0.0110': 6, '0.0065': 3, '-0.0205': 1, '-0.0145': 2, '-0.0150': 2, '0.0085': 1, '0.0090': 3, '-0.0022': 7, '-0.0068': 5, '-0.0128': 1, '0.0073': 1, '0.0013': 3, '0.0044': 8, '0.0081': 1, '-0.0017': 1, '-0.0061': 1, '0.0088': 1, '-0.0041': 3, '-0.0044': 8, '0.0076': 4, '0.0102': 2, '0.0043': 1, '-0.0007': 2, '-0.0042': 6, '0.0011': 2, '0.0029': 1, '-0.0049': 2, '-0.0046': 9, '-0.0009': 2, '-0.0011': 1, '-0.0101': 2, '0.0022': 3, '0.0058': 2, '-0.0047': 1, '0.0067': 1, '0.0092': 4, '-0.0002': 13, '0.0041': 1, '0.0089': 1, '-0.0021': 1, '0.0006': 11, '-0.0036': 8, '0.0024': 8, '-0.0059': 1, '0.0068': 1, '-0.0260': 1, '0.0062': 3, '0.0064': 2, '0.0004': 16, '0.0048': 3, '0.0086': 1, '0.0096': 3, '-0.0074': 3, '0.0042': 8, '0.0122': 1, '0.0014': 7, '0.0072': 2, '-0.0146': 1, '-0.0048': 6, '-0.0012': 8, '0.0094': 2, '0.0009': 2, '-0.0004': 10, '-0.0038': 6, '0.0034': 6, '0.0016': 12, '-0.0016': 6, '0.0056': 5, '-0.0084': 2, '-0.0026': 6, '-0.0006': 8, '0.0066': 3, '-0.0094': 3, '-0.0014': 8, '0.0019': 1, '0.0101': 1, '0.0186': 1, '0.0084': 1, '-0.0062': 1, '-0.0086': 2, '0.0002': 8, '-0.0072': 2, '0.0057': 2, '0.0033': 1, '-0.0033': 1, '0.0017': 1, '0.0026': 9, '-0.0032': 5, '0.0018': 9, '0.0054': 4, '-0.0155': 1, '0.0074': 3, '0.0194': 1, '0.0202': 1, '-0.0172': 1, '0.0036': 7, '-0.0092': 2, '0.0071': 1, '-0.0186': 1, '0.0162': 1, '-0.0226': 1, '-0.0154': 1, '-0.0066': 3, '-0.0112': 1, '-0.0124': 2, '-0.0106': 4, '0.0027': 1, '0.0082': 2, '-0.0148': 4, '-0.0176': 1, '-0.0024': 4, '-0.0058': 1, '-0.0018': 11, '0.0284': 1, '-0.0195': 1, '-0.0316': 1, '0.0134': 2, '-0.0108': 1, '-0.0136': 1, '-0.0034': 3, '0.0038': 6, '-0.0003': 2, '0.0256': 1, '-0.0073': 1, '-0.0054': 6, '0.0007': 1, '-0.0187': 1, '-0.0118': 1, '-0.0280': 1, '0.0174': 1, '-0.0008': 4, '0.0078': 3, '0.0278': 1, '0.0141': 1, '-0.0138': 2, '0.0091': 1, '0.0136': 1, '-0.0126': 1, '-0.0082': 1, '0.0046': 3, '-0.0203': 1, '-0.0116': 1, '-0.0179': 1, '0.0192': 2, '-0.0064': 2, '-0.0056': 1, '-0.0220': 1, '-0.0134': 1, '0.0114': 1, '-0.0152': 1, '-0.0076': 1, '0.0172': 1, '-0.0001': 1, '-0.0029': 1, '-0.0158': 1}

def most_common_rate_change(d):

'''(dict of {float:int}) -> list of float

Given d where keys are exchange rate changes and values are the number of occurrences of each exchange rate change, return the exchange rate changes that occur the most frequently. Note: there could be multiple exchange rate changes that occur most frequently.

'''

Answer 1

Please find the required python2.7 script that calculates the highest occurrence values as the following:

#==============================================================================

# Original Dictionary

key_value={'0.0045': 3, '0.0160': 2, '-0.0028': 6, '-0.0157': 1, '-0.0443': 1, '-0.0232': 1, '-0.0065': 9, '-0.0080': 12, '0.0052': 1, '-0.0052': 3, '-0.0283': 1, '-0.0087': 1, '-0.0020': 9, '-0.0290': 2, '0.0180': 3, '0.0030': 15, '-0.0170': 2, '0.0000': 63, '-0.0185': 3, '-0.0055': 5, '0.0148': 1, '-0.0053': 1, '0.0265': 1, '0.0010': 22, '-0.0015': 5, '0.0137': 1, '-0.0137': 2, '-0.0023': 2, '0.0008': 10, '0.0055': 6, '-0.0025': 6, '-0.0125': 2, '0.0040': 14, '0.0260': 1, '0.0070': 8, '0.0210': 1, '-0.0070': 8, '0.0395': 1, '-0.0040': 14, '-0.0255': 2, '0.0037': 3, '0.0060': 7, '0.0025': 7, '0.0095': 2, '-0.0100': 2, '-0.0085': 6, '-0.0248': 1, '0.0028': 8, '-0.0005': 7, '-0.0113': 1, '0.0418': 1, '-0.0075': 4, '0.0130': 4, '-0.0165': 1, '0.0020': 16, '-0.0090': 7, '0.0190': 4, '-0.0245': 1, '0.0240': 2, '-0.0225': 1, '-0.0230': 1, '-0.0295': 1, '-0.0330': 1, '-0.0139': 1, '0.0104': 1, '0.0032': 7, '-0.0117': 1, '-0.0035': 8, '-0.0010': 18, '0.0285': 1, '0.0012': 7, '-0.0202': 1, '-0.0098': 1, '0.0195': 1, '0.0075': 3, '0.0015': 8, '0.0005': 5, '-0.0130': 4, '0.0115': 1, '0.0245': 2, '0.0175': 1, '0.0155': 1, '0.0120': 3, '0.0185': 1, '-0.0078': 3, '0.0023': 2, '0.0340': 1, '-0.0105': 5, '0.0140': 2, '-0.0060': 9, '0.0125': 3, '0.0262': 1, '0.0143': 1, '-0.0120': 3, '-0.0380': 1, '-0.0095': 4, '0.0135': 2, '-0.0045': 6, '0.0100': 8, '0.0145': 2, '-0.0140': 6, '-0.0200': 1, '-0.0030': 11, '0.0035': 6, '-0.0175': 1, '0.0105': 3, '0.0080': 10, '0.0165': 3, '0.0050': 16, '0.0230': 1, '-0.0050': 3, '0.0170': 2, '-0.0110': 2, '-0.0115': 3, '0.0255': 1, '0.0300': 1, '0.0110': 6, '0.0065': 3, '-0.0205': 1, '-0.0145': 2, '-0.0150': 2, '0.0085': 1, '0.0090': 3, '-0.0022': 7, '-0.0068': 5, '-0.0128': 1, '0.0073': 1, '0.0013': 3, '0.0044': 8, '0.0081': 1, '-0.0017': 1, '-0.0061': 1, '0.0088': 1, '-0.0041': 3, '-0.0044': 8, '0.0076': 4, '0.0102': 2, '0.0043': 1, '-0.0007': 2, '-0.0042': 6, '0.0011': 2, '0.0029': 1, '-0.0049': 2, '-0.0046': 9, '-0.0009': 2, '-0.0011': 1, '-0.0101': 2, '0.0022': 3, '0.0058': 2, '-0.0047': 1, '0.0067': 1, '0.0092': 4, '-0.0002': 13, '0.0041': 1, '0.0089': 1, '-0.0021': 1, '0.0006': 11, '-0.0036': 8, '0.0024': 8, '-0.0059': 1, '0.0068': 1, '-0.0260': 1, '0.0062': 3, '0.0064': 2, '0.0004': 16, '0.0048': 3, '0.0086': 1, '0.0096': 3, '-0.0074': 3, '0.0042': 8, '0.0122': 1, '0.0014': 7, '0.0072': 2, '-0.0146': 1, '-0.0048': 6, '-0.0012': 8, '0.0094': 2, '0.0009': 2, '-0.0004': 10, '-0.0038': 6, '0.0034': 6, '0.0016': 12, '-0.0016': 6, '0.0056': 5, '-0.0084': 2, '-0.0026': 6, '-0.0006': 8, '0.0066': 3, '-0.0094': 3, '-0.0014': 8, '0.0019': 1, '0.0101': 1, '0.0186': 1, '0.0084': 1, '-0.0062': 1, '-0.0086': 2, '0.0002': 8, '-0.0072': 2, '0.0057': 2, '0.0033': 1, '-0.0033': 1, '0.0017': 1, '0.0026': 9, '-0.0032': 5, '0.0018': 9, '0.0054': 4, '-0.0155': 1, '0.0074': 3, '0.0194': 1, '0.0202': 1, '-0.0172': 1, '0.0036': 7, '-0.0092': 2, '0.0071': 1, '-0.0186': 1, '0.0162': 1, '-0.0226': 1, '-0.0154': 1, '-0.0066': 3, '-0.0112': 1, '-0.0124': 2, '-0.0106': 4, '0.0027': 1, '0.0082': 2, '-0.0148': 4, '-0.0176': 1, '-0.0024': 4, '-0.0058': 1, '-0.0018': 11, '0.0284': 1, '-0.0195': 1, '-0.0316': 1, '0.0134': 2, '-0.0108': 1, '-0.0136': 1, '-0.0034': 3, '0.0038': 6, '-0.0003': 2, '0.0256': 1, '-0.0073': 1, '-0.0054': 6, '0.0007': 1, '-0.0187': 1, '-0.0118': 1, '-0.0280': 1, '0.0174': 1, '-0.0008': 4, '0.0078': 3, '0.0278': 1, '0.0141': 1, '-0.0138': 2, '0.0091': 1, '0.0136': 1, '-0.0126': 1, '-0.0082': 1, '0.0046': 3, '-0.0203': 1, '-0.0116': 1, '-0.0179': 1, '0.0192': 2, '-0.0064': 2, '-0.0056': 1, '-0.0220': 1, '-0.0134': 1, '0.0114': 1, '-0.0152': 1, '-0.0076': 1, '0.0172': 1, '-0.0001': 1, '-0.0029': 1, '-0.0158': 1};

# Sorting based on values and storing as a new list in ascending order

new_dic = sorted(key_value.items(), key = lambda kv:(kv[1], kv[0]));

# Getting element with the maximum occurrences. It will the last element in an ascending list.

max_val = new_dic[len(new_dic)-1][1];

# printing all the highest values i.e. the number of occurrences

print 'The rates with highest occurrences are: ';

for i in new_dic:

if (i[1]==max_val):

print(i);

#==============================================================================

output:

The rates with highest occurrences are:
('0.0000', 63)