Question

Example 1: Define a function that takes an argument. Call the function. Identify what code is the argument and what code is the parameter.

Example 2: Call your function from Example 1 three times with different kinds of arguments: a value, a variable, and an expression. Identify which kind of argument is which.

Example 3: Create a function with a local variable. Show what happens when you try to use that variable outside the function. Explain the results.

Example 4: Create a function that takes an argument. Give the function parameter a unique name. Show what happens when you try to use that parameter name outside the function. Explain the results.

Example 5: Show what happens when a variable defined outside a function has the same name as a local variable inside a function. Explain what happens to the value of each variable as the program runs.

Answer 1

Ans ex 1 -

Output: 5

In this case both are same because this is both function declaration and definition

Ans 2 -

Output:

5

2

7

Ans 3 -

Output: This is because variable c has a scope limited to func only and it can not be accessed outside func.

Ans 4 -

Output:

It is same as example 4, local variables, even function parameters can only be accessed within the function.

Ans 5 -

Output:

3

4

This is because func has a variable that is known to func so it will use its own variable despite a global variable c is there defined outside it. Main do not have any local variable c and it can not access func's c so it will use global variable.