A student raises a 1-kg textbook 1 m off the surface of a table. How does...
A student raises a 1-kg textbook 1 m off the surface of a table. How does the work done by
gravity Wg on the book compare to the work done by the student Ws
on the book? Please give an in depth explanation, I know that the work done by the student will be greater. However, I do not understand why.
Homework Answers
Work done is defined as dot product of force and displacement.
Work done=(force magnitude)(displacement magnitude)(cos(theta.)),where theta is angle between force and displacement.
Here both force applied by student and gravity are equal in magnitude.
Here work done by student is positive and work done by gravity is negative.Because angle between student force and displacement is zeo degree.,but angle between gravity force and displacement is 180 degree.
So hence after raising 1 meter work done by student is greater than work done by gravity.
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