4. What percent of the observations from a Normal distribution lie between a standard score of –1 and a standard score of 2? (Hint: sketch a Normal curve.) A) 50% B) 61% C) 47.5% D) 81.5% E) 16%
Please Explain why.
solution:
P( -1< Z <2 )
= P(Z < 2) - P(Z <-1)
Using z table
= 0.9772-0.1587
=0.8185
= 81.5%

4. What percent of the observations from a Normal distribution lie between a standard score of...
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