
b.Encrypt the message block M=2 using RSA with the following parameters: e=23and n=233×241.
N=233*241=56153
P = 233, Q= 241, M=2, e =23

c. Compute a private key (d, p, q) corresponding to the given above public key (e, n).

d. Perform the decryption of the obtained ciphertext1.
1) without using the Chinese Remainder Theorem,
and
M = 21811^19367 mod 56153 = 2
2) using the Chinese Remainder Theorem.

Calculate using Excel or calculator: Test all odd numbers in the range from 233 to 241...
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