please help on both
1.)
We learned in section 6.1 that the Empirical Rule (a.k.a
68-95-99.7 rule) is a good estimate of probability within a
specific number of standard deviations from the mean for any normal
distribution.
We know that this rule only provides a good estimate and that it is
not very precise. With use of the Normalcdf function in our
calculator, we can find exact values. For example, when using the
Empirical Rule 95% is expected to be within 2 standard deviations
of the mean, when it is more precisely within standard
deviations of the mean.
Hint: To work this out, 1) sketch the distribution, 2) shade the
middle 95% of the data, 3) label an unkown z-score on the
horizontal axis on the upper end of the shaded portion, 4)
calculate the TOTAL percentage (area) to the LEFT of the uppermost
unknown z-scores, 5) finally, use invnorm to calculate the
uppermost z-score. (The z-score your calator gives you in this
final step is the value that you will put into the answer box
above.)
2.)
Assume that the readings at freezing on a batch of thermometers
are Normally distributed with mean 0°C and standard deviation
1.00°C.
Find P98, the 98-percentile of the distribution
of temperature readings. This is the temperature reading separating
the bottom 98% from the top 2%.
°C Round to 3 decimal places.
please help on both 1.) We learned in section 6.1 that the Empirical Rule (a.k.a 68-95-99.7...
A characteristic of the Normal models is the 68-95-99.7 Rule. But when we want to work with values that don't match up with this rule, we use one of two built-in commands in the graphing calculator. The commands are normalcdf and invNorm, and to find these commands, go to 2"d DISTR and choose option 2 or 3. Notes for normalcdf: The command format is normalcdf(lower bound, upper bound, mean, standard deviation). We use this command when we are looking for...
The Empirical Rule is also known as the 68-95-99.7 Rule. Use the Z-score table to find what each of these numbers really is. To assist you, include a sketch and a probability expression for each case. Please show your work, thanks.
Q2. The applications of the 68%-95%-99.7% Empirical Rule and Chebbysheff's Theorem (1) Please use your words to explain what is the 68%-95%-99.7% empirical rule. (2) Please use your words to explain what is the Chebbysheff’s Theorem. (3) Now, suppose there is a normally distributed data set with the mean of 30 and the standard deviation of 5, what can you say about the proportions of observations that lie between each of the following intervals: (i) 25 and 35? (ii) 20...
data valu es in a 7. The 68-95-99.7 rule for normal distributions states that 95% of the mally distributed data set will be within 2 standard deviations of the mear Generate numbers with a distribution that has fewer than 95% of the data values within 2 standard deviations of the mean. Can you generate a set that has many fewer than 95% of the data values within 2 standard deviations of the mean? How small can you make that percentage?...
Use the 68-95-99.7 rule to solve the problem. Assume that a distribution has a mean of 29 and a standard deviation of 4. What percentage of the values in the distribution do we expect to fall between 29 and 377 25% 5% 47.5% 95%
Use the 68-95-99.7 rule to solve the problem. Assume that a distribution has a mean of 29 and a standard deviation of 4. What percentage of the values in the distribution do we expect to fall between 29 and 37? 95% 5% 25% 47.5% Click comnloto this accorcmont
Use the 68-95-99.7 rule to solve the problem. Assume that a distribution has a mean of 21 and a standard deviation of 4. What percentage of the values in the distribution do we ex between 17 and 217 25% 34% 68% ОО 17% Question 35 of 40
2.5 points Use the 68-95-99.7 rule to solve the problem. Assume that a distribution has a mean of 21 and a standard deviation of 4. What percentage of the values in the distribution do we expect to fall between 17 and 212 68% 25% 17% 34%
Answer the following question involving "The Normal Distribution and the 68-95-99.7 Rule" and show how I got the answers below. Answers: 1)a) 68% b) 47.5% c) 2.5% 2) 12 or 13 people Questions: 1) A population of dogs have weights that are normally distributed with an average of 30 pounds with a standard deviation of 3 pounds. a) What percent of the dogs weigh between 27 and 33 pounds? b) What percent of the dogs weigh between 30 and 36...
Save Answer Question 38 25 points Use the 68-95-99.7 rule to solve the problem. Assume that a distribution has a mean of 21 and a standard deviation of 4. What percentage of the values in the distribution do we expect to fall between 17 and 21? 174 34 2516 68%