The composition of a hydrated tetramethylammonium-salt of a chromium(III)-oxalate complex ion conforms to the general formula:
| (N(CH3)4)xCr(C2O4)3·wH2O |
A 0.4986-g sample of this compound required 36.96 mL of 0.02909 M KMnO4 solution for the titration of all of the oxalate.
Molar mass = 5.565×102 g/mol
X = 3
What is w?
Ans:
When ‘X=3’ the formula takes the form (N(CH3)4)3Cr(C2O4)3·wH2O
Molar mass of the complex ion, M = 5.565×102 g/mol = 556.5 g/mol
Molar mass of H2O = 18 g/mol
Molar mass of the complex ion = Molar mass of the (N(CH3)4)3Cr(C2O4)3 + (w x 18)
Molar mass of the (N(CH3)4)3Cr(C2O4)3 = 538.49 g/mol (calculate from periodic table)
Molar mass of the complex ion = Molar mass of the (N(CH3)4)3Cr(C2O4)3 + (w x 18)
556.5 = 538.49 + (w x 18)
w = 1.00055556 ~ 1
So, w = 1
The composition of a hydrated tetramethylammonium-salt of a chromium(III)-oxalate complex ion conforms to the general formula:...
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BACKGROUND: Synthesis of Potassium Iron
(III) Oxalate Hydrate Salt
The iron(II) ions from
Fe(NH4)2(SO4)2•6H2O
will be precipitated as iron(II) oxalate.
Fe^2+(aq) + C2O4^2-(aq) --> FeC2O4 (s)
The supernatant liquid, containing the ammonium and sulfate
ions, as well as excess oxalate ions and oxalic acid will be
decanted and discarded. The solid will then be re-dissolved and the
iron(II) ions will be oxidized to iron(III) ions by reaction with
hydrogen peroxide.
2Fe^2+(aq) + H2O2(aq) --> 2Fe^3+(aq) +2 OH^ - (aq)
The...
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With the completion of the determinations of % potassium, %
iron, and % oxalate in the crystals, you may calculate the % water.
The percentage compositionof the crystals,
KxFe(C2O4)y ·
zH2O, has then been completely determined
experimentally. The simplest formula (x,y,z) can now be calculated
from the the percentage composition. Once the formula is know it is
then possible to calculate the percent yield of product that was
obtained in the preparation and purification of the crystals.
From Part A:...
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Help please??!
Molarity of KMnO4 is 0.0100 M
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