Question

Write a Complete Java program for the following specification:

One of the most popular games of chance is a dice game known as “craps,” which is played in casinos and back alleys throughout the world.

The rules of the game are straightforward:

A player rolls two dice. Each die has six faces. These faces contain 1, 2,3,4,5, and 6 spots. After the dice have come to rest, the sum of the spots on the two upward faces is calculated. If the sum is 7 or 11 on the first throw, the player wins. If the sum is 2, 3, or 12 on the first throw (called “craps”), the player loses (i.e., the “house” wins). If the sum is 4, 5,6,8,9, or 10 on the first throw, then that sum becomes the player’s “points.” To win, you must continue rolling the dice until you “make your points.” The player loses by rolling a 7 before making the points.

Answer 1

import java.util.Random;

public class DiceGame {
   public static void main(String[] args) {
       Random r = new Random();
       //rolling dice
       int d1 = r.nextInt(6) + 1;
       int d2 = r.nextInt(6) + 1;
       //finding sum
       int sum = d1 + d2;
       int points=0;
       int i=0;
       while (true) {
           System.out.println("Sum is : " + sum);
           //checking if sum is 11 or 7 in the first throw
          
           if (points==0 && (sum == 7 || sum == 11)) {
               System.out.println("Player losses");
               break;
           }
           //checking if sum is 2 3 12 in the first throw
           if(sum==2|| sum==3||sum==12){
               if(i==0)
               System.out.println("House wins");
               break;
           }
           i++;
           if (sum == 4 || sum == 5 || sum == 6 || sum == 8 || sum == 9 || sum == 10) {
               points=sum;
           }
           d1 = r.nextInt(6) + 1;
           d2 = r.nextInt(6) + 1;
           sum = d1 + d2;
           System.out.println("Player rolled "+d1+"+"+d2+" = "+sum);
       }
   }
}

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