A.) Calculate ∆G0 for a reaction with K = 5,219.2 at 298.15 K. Report your answer in kJ/mol.
B.) Calculate ∆G0 for a reaction with K = 0.05964 at 298.15 K. Report your answer in kJ/mol.
C.) Calculate the equilibrium constant at 298.15 K for a reaction with ∆G0 = -12.26 kJ/mol.
D.) Calculate the equilibrium constant at 298.15 K for a reaction that has a ∆G0 = 14.18 kJ/mol.
A.) Calculate ∆G0 for a reaction with K = 5,219.2 at 298.15 K. Report your answer...
A.) Calculate K for a reaction that has ∆H0 = -5.65 KJ/mol and ∆S0 = 43.75 J/mol K at 298.15 K. B.) Calculate ∆S0 for a reaction that has ∆H0 = 11.36 KJ/mol and K = 0.000376 at 298.15 K. Report your answer in J/mol K C.) Consider the reaction below. 2 NH3 ⇋ N2 + 3 H2 When 1.45 M NH3 wis allowed to decompose until equilibrium has been achieved, 0.87 M NH3 remains. If this reaction has ∆S0 =...
a.) Calculate the equilibrium constant for the following reaction at 298.15 K from cell potential data. Express the answer as lnK. Sn4+ + 2Fe2+ ----> Sn2+ + 2Fe3+ b.) Calculate the standard Gibbs free energy change in kJ/mol at 298.15 K for the following reaction from cell potential data: 3Sn4+ + 2Cr ----> 3Sn2+ + 2Cr3+
For the following reaction, find Q for the conditions Indicated 298 K). If ∆G0 is 20.2 kJ/mol, is this reaction at equilibrium? 2 A + B → C 0.25M 0.50M 0.75M
Calculate the equilibrium constant at 298.15 K for each of the following reactions from the value of ΔG° given. Please keep 2 significant figures. (a) H2(g) + 2 Na(s) → 2 NaH(s) ΔG° = −66.9 kJ/mol K= (b) 4 NO2(g) + O2(g) → 2 N2O5(g) ΔG° = 29.2 kJ/mol K= (c) SiO2(s) + 2 Cl2(g) → SiCl4(l) + O2(g) ΔG° = 236.5 kJ/mol K= †
Use the data below, for 298.15 K, to calculate the thermodynamic equilibrium constant, kp, at 641 K for the following reaction. NH4Cl(s) NH3(g) + HCl(g) ΔΗ /kJ mol-1 -314.4 -45.9 -92.3 Smº /JK-mol-1 94.6 192.8 186.9 Cp.m /JK-mol-1 84.1 35.1 29.1 Do not use the Van't Hoff equation, In(K/K) = -(AHR/R) (T2-1-T1-1) The value of the thermodynamic equilibrium constant is Kp = Number
Use the data below, for 298.15 K, to calculate the thermodynamic equilibrium constant, kp, at 839 K for the following reaction. NH4Cl(s) NH3(g) + HCl(g) ΔΗ 7 kJ mol-1 -314.4 -45.9 -92.3 Smº JK-1 mol-1 94.6 192.8 186.9 Cp,m 84.1 35.1 29.1 /JK-1 mol-1 Do not use the Van't Hoff equation, In(K /K1) = -(AHR/R) (T2-1 - 7,-1) The value of the thermodynamic equilibrium constant is Kp= 7.6e14
After the pictured problem, calculate the equilibrium
constant at 298.15 K for the reaction.
part 1 Calculate the equilibrium constant at 184 °C for a reaction that has a standard enthalpy of reaction, ΔH° = 30.2 kJ/mol and an equilibrium constant, K = 0.0603 at 10.6 °C. R = 8.314472 J⋅mol−1⋅K−1. Report your answer to THREE significant figures. part 2 The standard enthalpy of reaction (i.e. ΔH°) for a particular reaction is −31.7 kJ/mol. At 24.9 °C the equilibrium constant for the reaction is 3.96 × 10−2. Calculate the temperature (in °C) at which...
Calculate the equilibrium constant at 177 °C for a reaction that has a standard enthalpy of reaction, ΔH° = 21.3 kJ/mol and an equilibrium constant, K = 0.0612 at 40.5 °C. R = 8.314472 J⋅mol−1⋅K−1. Report your answer to THREE significant figures.
Calculate the equilibrium constant under standard conditions (K’eq) when (delta)G0’ is -4.18 kJ/mol. Standard conditions are 298 K and a gas constant = 8.32 x 10^-3 kJ/mol K