A physics instructor wants to produce a double-slit interference pattern large enough for her class to...
A physics instructor wants to produce a double-slit interference pattern large enough for her class to see. For the size of the room, she decides that the distance between successive bright fringes on the screen should be at least 2.40 cm.
If the slits have a separation d=0.0185mm, what is the minimum distance from the slits to the screen when 632.8-nm light from a He-Ne laser is used?
Homework Answers
sin(x) =m*lambda/d
x=sin^-1(m*lambda/d)
Put values ..
x=sin^-1(1*632.8*10^-9/0.0185*10^-3)
x=1.96 degrees
L=Y/tan(x ) =2.4*10^-2/tan(1.96)
L=70.13 cm (Answer)
I hope help you !!
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A physics instructor wants to produce a double-slit interference
pattern large enough for her class to...
A physics instructor wants to produce a double-slit interference pattern large enough for her class to...
A physics instructor wants to produce a double-slit interference pattern large enough for her class to see. For the size of the room, she decides that the distance between successive bright fringes on the screen should be at least 3.00 cm. If the slits have a separation d=0.0200mm, what is the minimum distance from the slits to the screen when 632.8-nm light from a He-Ne laser is used?
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A double-slit experiment has a slit separation distance of 0.08 mm. If the bright interference fringes are to be spaced 5 mm apart on the screen when the slits are illuminated with a laser of wavelength 633 nm, what should be the distance to the screen from the slits? 0.42 m 0.63 m 0.77 m 0.81 m 0.92 m
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