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At 25.0 °C, the galvanic cell constructed between the half-reactions below has K = 8.63x1013. What...

At 25.0 °C, the galvanic cell constructed between the half-reactions below has K = 8.63x1013. What is the value of E°cell, in volts, for this reaction? Enter your answer to the thousandths place.

HClO2(aq) + 3H+(aq) + 4e- ⇌ Cl-(aq) + 2H2O(l) H2O2(aq) + 2H+(aq) + 2e- ⇌ 2H2O(l)

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Answer #1

here total 4 electrons are flowing so, n = 4

T = 25 oC = 298 K

now delta Go = -RTln K = -nFEocell

so Eocell = RT ln K / nF

= ( 8.314 298 ​​​​​​​ ln ( 8.63​​​​​​​1013) /( 4 ​​​​​​​ 96500)

= 0.206 V

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