A chemist takes 280.0 mL of 1.800 M SrBr2 solution and dilutes it to a final...
A chemist takes 280.0 mL of 1.800 M SrBr2 solution and dilutes it to a final volume of 800.0 mL.
(a) What is the molarity of the dilute solution? .6300M
(b) How many grams of SrBr2 does the final volume of the dilute solution contain? Need this answer!
Homework Answers
Ans :
a)
We can use the formula :
M1V1 = M2V2
M1 = 1.800 M
V1 = 280.0 mL
V2 = 800.0 mL
Putting values :
1.800 x 280.0 = M2 x 800.0
M2 = .6300 M
So the molarity of the diluted solution will be .6300 M
b)
Number of mol = molarity x volume (L)
= .6300 x 0.800
= 0.504 mol
Mass of SrBr2 in grams = mol x molar mass
= 0.504 mol x 247.43 g/mol
= 124.7 grams
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