(a)
Annual demand, D = 384.61 * (52/2) = 10,000 units [Assuming
1 year = 52 weeks]
Ordering cost, K = 20
Unit carrying cost, h = 2
EOQ = (2.D.K / h)1/2 = SQRT(2*10000*20/2) = 447 units
(b)
Number of cycles on an average per annum = D / Q = 10000 / 447 = 22.37
(c)
F(z) = 0.955; z = NORMSINV(0.955) = 1.695
dLT = 384.61
σLT = 196.11
Safety stock, SS = z.σLT = 1.695*196.11 = 333 units (rounded up)
ROP = dLT + Safety stock = 384.61 + 333 = 718 units
(d)
Service level = 99.5%
So, probability of shortages = 0.5%
We have seen that the number of cycles = 22.37 in a year.
So, the expected number of cycles when a shortage occurs = 22.37 * 0.5% = 0.11185
So, the expected cost of shortage = 0.11185*$25 = $2.80
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