The life of Sunshine CD players is normally distributed with a mean of 4.1 years and a standard deviation of 1.3 years. A CD player is guaranteed for three years. We are interested in the length of time a CD player lasts. Find the probability that a CD player will last between 2.8 and eight years.
Solution :
Given that ,
mean =
= 4.1
standard deviation =
= 1.3
P(2.8< x <8 ) = P[(2.8 -4.1) /1.3 < (x -
) /
< (8 -4.1) / 1.3)]
= P( -1< Z <3 )
= P(Z <3 ) - P(Z <-1 )
Using z table
= 0.9987 -0.1587
probability= 0.8400
The life of Sunshine CD players is normally distributed with a mean of 4.1 years and...
The life of Sunshine CD players is normally distributed with a mean of 4.1 years and a standard deviation of 1.3 years. A CD player is guaranteed for three years. We are interested in the length of time a CD player lasts. Find the probability that a CD player will last between 2.8 and five years. Give the probability statement and the probability.
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