Suppose 49. g of butane is mixed with 150. g of oxygen.
Calculate the minimum mass of butane that could be left over by the
chemical reaction. Be sure your answer has the correct number of
significant digits.
2C4H10 + 13 O2 ---------> 8CO2 + 10H2O
according to balanced reaction
13 x 32 g O2 reacts with 2 x 58 g C4H10
150 g O2 reacts with 150 x 2 x 58 / 13 x 32 = 41.83 g C4H10.
mass of C4H10 left = 49 - 41.83 = 7.2 g
Suppose 49. g of butane is mixed with 150. g of oxygen. Calculate the minimum mass...
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