“Charley Chicken” and “Bradley Bee” are brands of canned tuna. During a week a certain amount of advertising appears for these products. There may be no advertising, one form of advertising (newspaper coupon), or two forms of advertising (coupon and a special store display). Let C denote the level of advertising for Charley Chicken. It can take the values c=0, 1 or 2. Let B denote the level of advertising for Bradley Bee; B can take the values b=0, 1 or 2. Suppose the following table represents the joint probability distribution of the advertising levels for these two brands of canned tuna.
|
Bradley Bee’s Advertising: B |
|||||
|
0 |
1 |
2 |
|||
|
0 |
0.05 |
0.15 |
0.25 |
||
|
Charley Chicken’s Advertising: C |
1 |
0.05 |
0.05 |
0.05 |
|
|
2 |
0.10 |
0.15 |
0.15 |
||
Find the marginal probability f(b=1).
Options:
F(b=1)=0.25
F(b=1)=0.30
F(b=1)=0.35
F(b=1)=0.40
F(b=1)=0.45
Solution:
The marginal probability is calculated as follows:
F(b=1)= P(b =1,c=0) + P(b=1,c=1) + P(b=1,c=2)
= 0.15 + 0.05 + 0.15
= 0.35
So option 3 is the correct answer.
“Charley Chicken” and “Bradley Bee” are brands of canned tuna. During a week a certain amount...
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