You arrive at a movie theater only to notice that there’s only one person selling tickets. You watch for some time and realize that on average about 80% of the time there is no one in the line or being served. People are clearly arriving randomly but on average every 30 seconds.
The average service time in seconds is:
Arrival rate = λ = 60/30 = 2 / min
Let Service Rate = μ / min
Probability of no customers in the system = Po = 1 - λ/μ = 80%
=> 1 - 2/μ = 0.80
=> μ = 2/(1 - 0.80) = 10 per minute
Hence, service rate = 60/10 = 6 secs per customer
You arrive at a movie theater only to notice that there’s only one person selling tickets....
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Customers arrive at a movie theater at the advertised movie time only to find that they have to sit through several previews and prepreview ads before the movie starts. Many complain that the time devoted to previews is too long. A preliminary sample conducted by The Wall Street Journal showed that the standard deviation of the amount of time devoted to previews was five minutes. Use that as a planning value for the standard deviation in answering the following questions....
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