Question

A franchise of a chain of coffee restaurants sees an average of 5 customers enter the...

A franchise of a chain of coffee restaurants sees an average of 5 customers enter the restaurant per hour. What is the probability that 0 customers enter the restaurant in an hour? Round your answer to 4 decimal place

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Answer #1

Solution :

Given that ,

mean = = 5

Using Poisson probability formula,

P(X = x) = (e- * x ) / x!

P(X = 0) = (e-5 * 50) / 0! = 0.0067

Probability = 0.0067

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