A franchise of a chain of coffee restaurants sees an average of 5 customers enter the restaurant per hour. What is the probability that 0 customers enter the restaurant in an hour? Round your answer to 4 decimal place
Solution :
Given that ,
mean =
= 5
Using Poisson probability formula,
P(X = x) = (e-
*
x ) / x!
P(X = 0) = (e-5 * 50) / 0! = 0.0067
Probability = 0.0067
A franchise of a chain of coffee restaurants sees an average of 5 customers enter the...
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