Calculate P(0.2<=X<=0.4) for the following discrete probability mass function: X = {0.1, 0.2, 0.3, 0.4} and f(x) = {0.29, 0.15, 0.35, 0.21}
f (X) = P (X=x)
Given P (X = 0.1) = 0.29
P (X= 0.2) = 0.15
P (X= 0.3) = 0.35
P (X= 0.4) = 0.21
We need to find
P ( 0.2
0.4 ) = P (X=0.2)+P(X=0.3)+P (X=0.4)
= 0.15 + 0.35 + 0.21
= 0.71
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