Solve the following recurrence by giving the tightest bound possible. T(n) = 4T(n/4) + 4n

Question

Question

engineering Computer-Science

Answer 1

Answer #1

T(n) = 4T(n/4) + 4n

Master Theorem:

As per Master Theorem,

a = 4, b = 4, k = 1 and p = 0

Clearly, a = b^k and p > -1, hence

T(n) = Θ(n^log₄4 * log n) = Θ(n log n)

Answer 2

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