I need 500 mL of 0.2 M acetate, pH 5.0. I have solid anhydrous sodium acetate...
I need 500 mL of 0.2 M acetate, pH 5.0. I have solid anhydrous sodium acetate (MW=82 g/mol^-1) and a solution of 1M acetic acid. Describe how to make the buffer.
Homework Answers
total moles of buffer = 0.5 L x 0.2 mole / L = 0.1
x (acetic acid ) + y (sodium acetate) = 0.1 -----------------> (1)
pH = pKa + log (y / x)
5.0 = 4.76 + log (y/x )
log (y/x ) = 0.24
y / x = 1.74
y = 1.74 x -----------------------> 2
by solving 1 and 2
x = 0.0365
y = 0.0635
moles of acetic acid = 0.0365
molarity of aceitic acid given = 1 M
molarity = moles / volume
1 = 0.0365 / volume
volume = 0.0365 / 1 = 0.0365 L
volume = 36.5 mL
moles of sodium acetate = 0.0635
mass of sodium acetate = 0.0635 x 82 = 5.21 g
to prepare this buffer : 5.21 g soild sodium acetate and 36.5 mL acetic acid must be taken
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