Question

Question 3 options:

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Let Z denote a standard normal random variable. Find the probability P(Z < -1.12)? The area to the LEFT of -1.12?

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Enter in format X.XX rounding UP so one-half (1/2) is 0.50 and two-thirds (2/3) is 0.67 with rounding. Enter -1.376 as -1.38 with rounding. NOTE: DO NOT ENTER A PERCENTAGE (%).

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Let Z denote a standard normal random variable. Find the probability P(Z > 0.84)? The area to the RIGHT of 0.84?

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Enter in format X.XX rounding UP so one-half (1/2) is 0.50 and two-thirds (2/3) is 0.67 with rounding. Enter -1.376 as -1.38 with rounding.  NOTE: DO NOT ENTER A PERCENTAGE (%).

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Let Z denote a standard normal random variable. Find the probability P(-1.18<Z<1.64)? The area BETWEEN -1.18 and 1.64?

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Enter in format X.XX rounding UP so one-half (1/2) is 0.50 and two-thirds (2/3) is 0.67 with rounding. Enter -1.376 as -1.38 with rounding. NOTE: DO NOT ENTER A PERCENTAGE (%).

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Let Z denote a standard normal random variable. Find the z-score for the 56th percentile?

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Enter in format X.XX rounding UP so one-half (1/2) is 0.50 and two-thirds (2/3) is 0.67 with rounding. Enter -1.376 as -1.38 with rounding.  NOTE: DO NOT ENTER A PERCENTAGE (%).

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Let Z denote a standard normal random variable. Find the z-score for with the area to the RIGHT equal to 0.14?

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Enter in format X.XX rounding UP so one-half (1/2) is 0.50 and two-thirds (2/3) is 0.67 with rounding. Enter -1.376 as -1.38 with rounding.  NOTE: DO NOT ENTER A PERCENTAGE (%).

Answer 1