Given the equation, H2O(g) + C(s) --> H2(g) + CO(g). Assume the temp does not change during the reaction (delta H and delta S do not change during the reaction and C(s) is graphite). Using the appendix, calculate the delta G. Then determine the lowest possible temp at which the reaction will be spontaneous.
The given equation is

The data for
for each of the component at 298.15 K standard temperature is
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|
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-241.8 | 0.189 |
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0 | 0.00574 |
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0 | 0.131 |
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-110.5 | 0.197 |
Hence, the standard free energy change for the reaction can be calculated as

From the data above,

Similarly.

Hence, at T = 298.15 K, assuming the enthalpies and entropies remain constant.

We know that a reaction is spontaneous if the free energy change
.
For our given reaction, the critical temperature at which
can be calculated as

Hence, above 235.33 K
which makes
.
Hence, the minimum temperature at which the reaction is spontaneous
is 235.33 K
Note: the answer might vary slightly depending upon the number of significant figures you take for the values in appendix.
Given the equation, H2O(g) + C(s) --> H2(g) + CO(g). Assume the temp does not change...
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question 17.57
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