Find Kc for the reaction 2 NO(g) + O2(g) ↔ 2NO2(g), given Kp = 2.2 x 1012 @ 25 °C. R = 0.08206 L.atm/mol.K
Find Kc for the reaction 2 NO(g) + O2(g) ↔ 2NO2(g), given Kp = 2.2 x...
Calculate Kp for the following (R = 0.08206 L.atm/mol.K): a) N2O4(g) ->2NO2(g) Kc = 5.9 x 10 -3 (at 298 K) b) N2(g) + O2(g) -> 2NO(g) Kc = 4.10 x 10 -31 (at 298 K)
For the equilibrium reaction, 2 S03 - 2 SO2 (g) + O2 (g), Kc is 4.08 x10-3 at 1000 K. Calculate the value for Kp. (R 0.0821 L.atm/ mol.K) A. 9.60 B. 2.99 OC. 4.97 x 10-5 OD.0.335
Consider the equilibrium constant Kc for the reaction: N2O4(g) ↔ 2NO2(g) is 0.211 at 100°C. What is the value for the equilibrium constant if the reaction is reversed: 2NO2(g) ↔ N2O4(g) ? A. -0.211 B. 0.211 C. 4.74 D. -4.74
Consider the equilibrium constant Kc for the reaction: N2O4(g) ↔ 2NO2(g) is 0.211 at 100°C. What is the value for the equilibrium constant is the reaction is balanced as ½ N2O4(g) ↔ NO2(g) ? A. 0.106 B. 0.459 C. 0.211 D. 0.422
For the equilibrium: 2 SO3(g) < = > O2(g) + 2 SO2(g) Kp = 0.269 at 625 oC What is Kc at this temperature? Kp = Kc[RT]Δn R = 0.08206 L-atm/mol K
2) For the equilibrium: 2 SO3(g) <=> O2(g) + 2 SO2(g) Kp = 0.269 at 625 °C What is Ke at this temperature? Kp = Kc[RT]An R = 0.08206 L-atm/mol K
3. Given Kc or Kp for the following reactions, what is the value of Kp or Ke? (a) 12 (g) + Cl2 (a) 22ICI (g): Kc = 2.0 x105 at 25°C (b) N204(g) + 2NO2(0); Kc = 0.90 at 120 °C (c) CaCO3(s) = Cao (s) + CO2 (ox Kp = 1.67 x 102 at 740 °C 4. A container contains an equilibrium mixture of H2 (g), 12(g), and Hl) at 721 K. The concentration of each substance present at...
Given the Kp = 0.015 at 45 °C for the reaction 4 Ag(s) + O2(g) 2 Ag2O(s). Which of the following is the Kc for the reaction? (R = 8.314 J/K-mol = 0.0821 L-atm/K-mol)
Given the chemical equation, 2 H2O(g) ↔ 2 H2(g) + O2(g) calculate Kp at 1007 K given that the partial pressures of H2O, H2 and O2 at equilibrium are 0.460 bar, 0.055 bar, and 0.045 bar, respectively.
6. What is the Kp of the following reaction if Kc is 5.31 at 723 °C? O2 (g) + 3UO2Cl2 (g) ↔ U3O8 (s) + 3Cl2 (g)