How many bits do you need to store 584 in the memory? Why?
584 can b divided into powers of 2 as follows:
584 = 512 + 64 + 8
= 29 + 26 + 23
--> We can write that into binary as:
1001001000
--> Total bits are 10.
--> So, 10 bits are needed to store 584 in memory.
Determine the minimum number of bits you would need for a memory address if memory could have up to 68GBytes. Assume byte addressing and explain how do you arrived at answer?? A).Since there is no calculator available, solve it by estimation method. B). If a calculator is available, show me alternative approach to solve the problem.
Problem 1.0-20 Points A certain memory has a word size of 8K x 32. How many words does it store? What is the number of bits per word? How many memory cells does it contain?
Problem 1.0-20 Points A certain memory has a word size of 8K x 32. How many words does it store? What is the number of bits per word? How many memory cells does it contain?
How many address lines are needed for memory with 512 locations? How many bits are present in 4k x 8 SARM IC?
For a byte-addressable memory, how many address bits are needed for 128 MB memory? Show your work.
computer architecture
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how many unique RAM memory bytes can a CPU access if it has 22 lines/bits on the address bus?
Question 4 (1 point) How many bits do we need to represent the decimal number 359 in binary? Convert this answer to binary. 1001 1010 1100