A 78-nFnF parallel-plate capacitor has plates that sandwich a dielectric layer that is 75 μmμm thick....
A 78-nFnF parallel-plate capacitor has plates that sandwich a dielectric layer that is 75 μmμm thick.
Calculate the thickness of the dielectric layer that would reduce the capacitance to 63 nFnF.
Express your answer to two significant figures and include appropriate units.
Homework Answers
given
intial capacitance ci = 78*10^-9 F
thickness ti = 75*10^-6 m
from the relation
capacitance c = A
/t
here area and medium same
ci*ti = cf*tf
tf = 78*10^-9*75*10^-6/63*10^-9
tf = 92.86*10^-6 m
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