If you mix 60mL of 0.2 M acetic acid with 80mL of 0.4 M acetate, what will be the resulting pH. Then how many total milliliters of 1M NaOH can you add to the solution and still have a good buffer? (that is, within 1 pH unit of pKa).
1)
mmoles of acetic acid = 60 x 0.2 = 12
mmoles of acetate = 80 x0.4 = 32
pH = pKa + log (acetate / acetic acid )
pH = 4.74 + log(12 / 32)
pH = 4.31
2)
pH = pKa + log (acetate + V / acetic acid - V)
5.74 = 4.74 + log (acetate + V / acetic acid - V)
(acetate + V / acetic acid - V) = 10
12 + V / 32 - V = 10
12 + V = 320 - 10V
11 V = 308
V = 28 mL
volume of NaOH needed = 28 mL
If you mix 60mL of 0.2 M acetic acid with 80mL of 0.4 M acetate, what...
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