A titration of pure vitamin C was performed by titrating a sample of vitamin C solution...
A titration of pure vitamin C was performed by titrating a sample of vitamin C solution with 23.35 mL of a 0.43 M Iodine solution. If there was 20.0 mL of vitamin C in the flask, what was the initial concentration of the vitamin C solution? The vitamin C solution was not diluted.
Homework Answers
Chemical name of vitamin c is ascorbic acid.
I2 + vitamin c 
dehydroascorbic
acid + 2I- + 2H+.
so, moles of vitamin c = moles of Iodine
Volume of Iodine *molarity = volume of vitamin c * molarity
So, 23.3*0.43 = 20.0 * M
Or, M = 0.50095
Hence , initial concentration of vitamin C = 0.50095 M
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A titration of pure vitamin C was performed by titrating a
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1. A student performed the titration as in this experiment. He transferred a 2.00 mL sample of the acid into a flask, diluted it with water, and then began to add sodium hydroxide solution from the buret. After adding 50 mL of NaOH solution, the sample in the flask still had not turned pink. What error did the student make?
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please answer these questions below
Experiment 7: Titration II volume of deionized water so that(20 mL of solution contains 40 mg of vitamin C. For example, if you have a 500-mg tablet, crush it up and dissolve it entirely in 250 mL of deionized water. Then use 20 mL of that solution for standardization. Is the quantity 20 mL important? What would happen if you used 250 mL? Place the buret in the clamp on the ring stand. Using a...
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In the table below is represented the data for a similar titration for Vitamin C analysis. Use the data below to calculate the concentration of Vitamin C in mg/mL of juice. Given that the lodine Solution used for the titration has been standardized against a known Vitamin C solution and its was determined that 1 mL of lodine - 1.50 mg Vitamin C. Buret Reading Trial 1 Trial 2 Initial Buret Reading 0.0 mL 4.8 mL Final Buret Reading 4.8...
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