Question

You are playing the game of Monopoly and you decide you wish to construct houses on one of your property groups. The rules of the game require that the number of houses on the properties within each group may not differ by more than one.

You will be given an amount of money to spend, the cost per house, and the number of properties in the group. The goal is to determine how many houses will go on each. And to appear more conversational, the last line of output will use words to represent numbers instead of digits.

To make the program simple, you may assume that you will not have enough money to build past four houses per property (twelve total).   You do not need to convert the price of a house to a word (although that can be done rather simply).

Here is a small table relating the colors of the monopoly property groups, the number of properties within the group, and the cost of the houses.

color	size	cost
purple	2	50
light blue	3	50
maroon	3	100
orange	3	100
red	3	150
yellow	3	150
green	3	200
dark blue	2	200

Sample Interfaces:

Which color block will you be building on?  orange
How much money do you have to spend?   860
There are three properties and each house costs 100 
You can build eight house(s) -- one will have two and two will have three

Which color block will you be building on?  dark blue 
How much money do you have to spend?  250
There are two properties and each house costs 200
You can build one house(s) -- one will have none and one will have one

The information above relates to a previous homework assignment. Below is the continuation of that assignment but in more detail. This is the part I need help with.

The previous assignment had a simplifying assumption that the amount of money would be limited, such that the builder could not afford more than four houses on any property. This assignment will lift that restriction.

There is nothing really special about building hotels in Monopoly. That purchase is simply equal to the price of five houses, and is built only in the same circumstances that would permit five houses (no other property may have fewer than four).

The inputs to the program will be essentially the same -- the color of a property group and the amount of money to be spent. But the following cases should be addressed:

• if no building is affordable, display "You cannot afford even one house." instead of building 0 houses everywhere.
• if one can afford to build 5 houses somewhere, announce that a hotel is being built instead of 5 houses.
• if one can afford to build more than 5 houses somewhere, only build one hotel and nothing else
• omit the word 'none' in the output (i..e don't say 'one property has none' or 'none have two')

Hint: The simplest and clearest solutions will use 'else' and 'elif' and will not need 'and' or 'or'.
A portion of your grade is based on how clear your code is, and how well it avoids producing contradictory output.

Answer 1

As per the given details the program should be as follows :

color = input("Which color block will you be building on? ")

m = int(input("How much money do you have to spend? "))

if(color == "purple"):

print("There are 2 properties and each house costs 50 ")

b = (m/50+1)/2

a = b-1

print("You can build "+str(int(m/50))+" house(s) -- 1 will have "+str(int(a))+"and 2 will have "+str(int(b)))

elif(color == "light blue"):

print("There are 3 properties and each house costs 50 ")

b = (m/50+1)/3

a = b-1

print("You can build "+str(int(m/50))+" house(s) -- 1 will have "+str(int(a))+"and 2 will have "+str(int(b)))

elif(color == "maroon"):

print("There are 3 properties and each house costs 100 ")

b = (m/100+1)/3

a = b-1

print("You can build "+str(int(m/100))+" house(s) -- 1 will have "+str(int(a))+"and 2 will have "+str(int(b)))

elif(color == "orange"):

print("There are 3 properties and each house costs 100 ")

b = (m/100+1)/3

a = b-1

print("You can build "+str(int(m/100))+" house(s) -- 1 will have "+str(int(a))+"and 2 will have "+str(int(b)))

elif(color == "red"):

print("There are 3 properties and each house costs 150 ")

b = (m/150+1)/3

a = b-1

print("You can build "+str(int(m/150))+" house(s) -- 1 will have "+str(int(a))+"and 2 will have "+str(int(b)))

elif(color == "yellow"):

print("There are 3 properties and each house costs 150 ")

b = (m/150+1)/3

a = b-1

print("You can build "+str(int(m/150))+" house(s) -- 1 will have "+str(int(a))+"and 2 will have "+str(int(b)))

elif(color == "green"):

print("There are 3 properties and each house costs 200 ")

b = (m/200+1)/3

a = b-1

print("You can build "+str(int(m/200))+"house(s) -- 1 will have "+str(int(a))+"and 2 will have "+str(int(b)))

elif(color == "dark blue"):

print("There are 2 properties and each house costs 200 ")

b = (m/200+1)/2

a = b-1

print("You can build "+str(int(m/200))+"house(s) -- 1 will have "+str(int(a))+"and 1 will have "+str(int(b)))

else:

print("Wrong input")

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