Question

There was produced 19.55g metallic potassium during the electrolysis of molten KCl. Calculate the amount (volume) of Cl2 (standard conditions) obtained. Assume that the current efficiency was equal to 100%. Molecular weights are: MK = 39.1 g; MKCl = 74.6g MCl2 = 71.0g

Please ,follow instructions strictly and write legibly.

Answer 1

Ans :

Number of mol of potassium = mass / molar mass

= 19.55 g / 39.1 g/mol

= 0.5 mol

The KCl compounds has equimolar amounts of both potassium and chlorine , so number of mol of chlorine atoms = 0.5 mol

Mol of Cl2 = 0.5 mol / 2 = 0.25 mol

Each mol at standard conditions , occupy 22.4 Liters of volume

so here , the volume of Cl2 gas obtained will be : 0.25 mol x 22.4 L/mol

= 5.6 L