A manufacturer knows that their items have a normally
distributed lifespan, with a mean of 7.5 years, and standard
deviation of 1.8 years.
If you randomly purchase one item, what is the probability it will
last longer than 12 years?
Solution :
Given that,
mean =
= 7.5
standard deviation =
= 1.8
P(X>12 ) = 1 - P[(X-
) /
< (12 - 7.5) /1.8 ]
= 1 - P(z < 2.5)
Using z table
= 1 - 0.9938
=0.0062
A manufacturer knows that their items have a normally distributed lifespan, with a mean of 7.5...
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