Amarillo Slim, a professional dart player, has an 80% chance of hitting the bull's eye on a dartboard with any throw. Assume each throw at the dartboard is independent of any other throw.
Suppose, now that Amarillo Slim throws 10 darts, one at a time, at the dartboard. What is the probability he gets exactly 7 bull's eyes? (to 4 decimals)
Solution
Given that ,
p = 0.80
q = 1 - p = 1 - 0.80 = 0.20
n = 10
Using binomial probability formula ,
P(X = x) = (n C x) * p x * (1 - p)n - x
P(X = 7) = (10 C 7) * 0.80 7 * (0.20)10 - 7
Probability =0.2013
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