For the combustion reaction, C4H8(gas) + 6 O2(gas) → 4 CO2(gas) + 4 H2O(liq), at 25oC, the enthalpy change is ∆H = -2630 kJ. What is ∆U for this reaction?
the answer is -2622.6 kJ please show work and explain
For the combustion reaction, C4H8(gas) + 6 O2(gas) → 4 CO2(gas) + 4 H2O(liq), at 25oC,...
For the combustion of cyclopropane at 25 ºC C3H6(g) + (9/2) O2(g) → 3 CO2(g) + 3 H2O(liq) ΔHºc(C3H6,g) = -2091 kJ / mol. What is the standard molar enthalpy of formation of cyclopropane(g) at 25 ºC if the standard molar enthalpies of formation of CO2(g) and H2O(liq) at that temperature are, respectively, -393.51 kJ / mol and -285.83 kJ / mol?
the enthalpy of combustion of CH4(g) to make H2O(l) and CO2(g) is -2340 kJ mol-1. The enthalpy of combustion of CH2(g) to make H2O(l) and CO2(g) is -2760 kJ mol-1. The enthalpy of formation of H2O(l) is -286 kJ mol-1. All the data are for 298 K. The heat capacities for O2(g), CHA(8), CH3(g), H2O(l) and CO2(8) are 29, 61, 71, 75 and 37 JK"mor", respectively. Deduce a) 4U298 for the combustion of C4H8(g). 5) AH for the combustion of...
The combustion reaction of ethane is as follows. C2H6(g) + 7/2 O2(g) → 2 CO2(g) + 3 H2O(l) Using Hess's law and the reaction enthalpies given below, find the change in enthalpy for this reaction. reaction (1): C(s) + O2(g) → CO2(g) ΔH = −393.5 kJ/mol reaction (2): H2(g) + 1/2 O2(g) → H2O(l) ΔH = −285.8 kJ/mol reaction (3): 2 C(s) + 3 H2(g) → C2H6(g) ΔH = −84.0 kJ/mol
1. Calculate the standard enthalpy of combustion for the following reaction: C6H12O6 (s) + 6 O2 (g) ---> 6 CO2 (g) + 6 H2O (l) To solve this problem, we must know the following ΔH°f values: C6H12O6 (s) -1275.0 O2 (g) zero CO2 (g) -393.5 H2O (l) -285.8 5. 2. Using the reaction and ΔH from #1, calculate how many liters of oxygen gas will be used to produce 11,000 kJ of energy at 745 mmHg and 90°C.
The change in Hrxn for the reaction C8H8 + 10 O2 = 8 CO2 + 4 H2O is -4395 kJ/mol. Knowing this, as well as the standard enthalpies of formation below, calculate the standard enthalpy of formation of Styrene in kJ/mol. change in Hf[CO2 (g)] = -393.5 kJ/mol change in Hf[H2O (l)] = -285.8 kJ/mol
The thermochemical equation for the combustion of propane is: C3H8 (g) + 5 O2 (g) 3 CO2 (g) + 4 H2O (l) H = -2220 kJ What is the enthalpy change when 35.0 g of propane react?
2) Consider the combustion reaction of ethylene at 25 °C and 1 bar, but in the case that H20 is produced as a gas rather than a liquid: C2Halg)+3 O2(g)>2 CO2(g) + 2 H20(g) What is the standard enthalpy of the reaction? Information that may be useful for the calculation is given below (at the same temperature and pressure): C2H4(g)3 O2(g) -»2 CO2(g)+ 2 H2O(liq) AtusH(H20) 6.008 kJ mol-; AvaphH°(H2O) = 44.016 kJ mol-; AtH°(H20,g) = -241.82 kJ mol- (A)-1410.0...
The combustion of hexane is given by the following reaction. 2 C6H14 + 19 O2 12 CO2 + 14 H2O The enthalpy of reaction is −4163.0 kJ/mol. How much energy (in joules) will be released if 82.22 grams of hexane is burned. (Molar mass of hexane = 86.20 g/mol). J
7) Find AH° for the reaction C3Hg(8) + 5 O2(8) - 3 CO2(8) + 4 H2O(l). AH° = -2046 kJ for the reaction: C3H8(8) + 5 O2(8) - 3 CO2(g) + 4H2O(8) The heat of vaporization of water is 44.0 kJ/mol. The standard enthalpy of formation of water and water vapor are -285.9kj/mol and -241.8 kj/mol, respectively. Note that H20 is a liquid in the first reaction and a gas in the second. 0-1870 kJ 0-2222 kJ O-2002 kJ 0-2090...
Show the calculation of the volume of H2O gas formed by the combustion of 18.6 grams of C6H6 at 30oC and 1.10 atm?The combustion of benzene (C6H6) takes place by the following reaction equation. 2 C6H6 (g) + 15 O2 (g) → 12 CO2 (g) + 6 H2O (g) Please Help!