1. A research company surveyed 650 adults in the US to estimate what percent of the country were afraid of their identity being stolen. From the sample, 408 indicated that they were afraid of their identity being stolen. Find the 92% confidence interval for the proportion of all adults in the US who are afraid of their identity being stolen. Round to 4 decimal points.
2. A laboratory tested 90 chicken eggs and found that the mean amount of cholesterol was 213.5 milligrams with a standard deviation of 19.0 milligrams. Construct a 95% confidence interval for the true mean cholesterol content, μ, of all such eggs. round to 4 decimals
3. A random sample of 86 light bulbs had a mean life of 545 hours with a standard deviation of 29 hours. Construct a 90% confidence interval for the mean life, μ, of all light bulbs of this type. round to 4 decimals.
4. A government agency would like to know the average weight of adult catfish in the wild. The need to know how many fish to sample. The population standard deviation is known to be 16.8 lbs from previous studies.
(a) Assuming that they would like to be 90% confident of the results, what is the critical value that corresponds to this given level of confidence? Round to two decimals and remember that critical values are defined to be positive.
(b) If they would like to have a maximum error of 1.4 lbs, how many fish should be sampled?
5. The US government spent $4.5 billion (about $16 per resident) on the 2000 census. As a money savings device, statisticians have recommended the use of sampling techniques as opposed to polling the entire population. Based on the 2000 census, the population standard deviation of ages in the US is known to be 22.57 years.
(a) Assuming that we would like to be 99% confident of the results, what is the critical value that corresponds to this given level of confidence? Round to two decimals and remember that critical values are defined to be positive.
(b) If we would like to have a maximum error of 0.15 years, how many residents should be sampled?
6. A brochure claims that the average maximum height for a
certain type of plant is 0.7 m. A gardener suspects that this is
not accurate locally due to variation in soil conditions, and
believes the local height is shorter. A random sample of 40 mature
plants is taken. The mean height of the sample is 0.65 m with a
standard deviation of 0.20 m. Test the claim that the local mean
height is less than 0.7 m using a 5% level of significance.
a. Enter the Null Hypothesis for this test: H0:
b. Enter the Alternative Hypothesis for this test: H1:
c. Is the original claim in the Null Hypothesis (H0) or the
Alternative Hypothesis (H1)? Answer using either H0 or H1.
d. What is the p-value for this hypothesis test? Round your answer
to four decimal places.
e. What is the decision based on the given sample statistics?
f. What is the correct interpretation of the decision?
There
enough evidence to
the claim that the mean height of the plant locally is different from 0.7 m.
1. A research company surveyed 650 adults in the US to estimate what percent of the...
Test the claim that the mean GPA of night students is smaller than 2.8 at the .10 significance level. The null and alternative hypothesis would be: H1 : p < 0.7 H1ιμ>2.8 H1 : μ < 2.8 Ho:p 0.7 Ho:p 0.7 Ho: 2.8 The test is: left-tailed right-tailed two-tailed Based on a sample of 65 people, the sample mean GPA was 2.76 with a standard deviation of 0.05 The test statistic is: decimals) The critical value is: decimals) Based on...
1. Test the claim that the mean GPA of night students is significantly different than 2.4 at the 0.2 significance level. The null and alternative hypothesis would be: a) H0:μ=2.4 H1:μ>2.4 b) H0:μ=2.4 H1:μ<2.4 c) H0:p=0.6 H1:p<0.6 d) H0:p=0.6 H1:p>0.6 e) H0:p=0.6 H1:p≠0.6 f) H0:μ=2.4 H1:μ≠2.4 2. The test is: a) left-tailed b) right-tailed c) two-tailed 3. Based on a sample of 35 people, the sample mean GPA was 2.44 with a standard deviation of 0.04 The test statistic is:...
A manufacturer of light bulbs advertises that, on average, its long-life bulb will last more than 5500hours. To test this claim, a statistician took a random sample of 90 bulbs and measured the amount of time until each bulb burned out. The mean lifetime of the sample of bulbs is 5551 hours and has a standard deviation of 420 hours. Can we conclude with 99% confidence that the claim is true? Fill in the requested information below. (a) The value...
Test the claim that the mean GPA of night students is larger than 2.6 at the .10 significance level. The null and alternative hypothesis would be: H0:p=0.65H0:p=0.65 H1:p<0.65H1:p<0.65 H0:p=0.65H0:p=0.65 H1:p>0.65H1:p>0.65 H0:μ=2.6H0:μ=2.6 H1:μ<2.6H1:μ<2.6 H0:μ=2.6H0:μ=2.6 H1:μ>2.6H1:μ>2.6 H0:μ=2.6H0:μ=2.6 H1:μ≠2.6H1:μ≠2.6 H0:p=0.65H0:p=0.65 H1:p≠0.65H1:p≠0.65 The test is: left-tailed right-tailed two-tailed Based on a sample of 50 people, the sample mean GPA was 2.61 with a standard deviation of 0.02 The test statistic is: (to 2 decimals) The critical value is: (to 2 decimals) Based on this we: Reject...
Test the claim that the mean GPA of Orange Coast students is significantly different than the mean GPA of Coastline students at the 0.01 significance level. The null and alternative hypothesis would be: H0:pO≤pC H1:pO>pC H0:μO≥μC H1:μO<μC H0:pO=pC H1:pO≠pC H0:pO≥pC H1:pO<pC H0:μO=μC H1:μO≠μC H0:μO≤μC H1:μO>μC The test is: left-tailed two-tailed right-tailed The sample consisted of 30 Orange Coast students, with a sample mean GPA of 2.96 and a standard deviation of 0.07, and 30 Coastline students, with a sample mean...
Test the claim that the mean GPA of night students is smaller than 2.2 at the 0.10 significance level. The null and alternative hypothesis would be: H0:p≥0.55 H1:p<0.55 H0:μ≤2.2 H1:μ>2.2 H0:p≤0.55 H1:p>0.55 H0:p=0.55 H1:p≠0.55 H0:μ=2.2 H1:μ≠2.2 H0:μ≥2.2 H1:μ<2.2 The test is: two-tailed left-tailed right-tailed Based on a sample of 60 people, the sample mean GPA was 2.17 with a standard deviation of 0.04 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals)
Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.05 significance level. The null and alternative hypothesis would be: H0:pO≥pCH0:pO≥pC H1:pO<pCH1:pO<pC H0:pO≤pCH0:pO≤pC H1:pO>pCH1:pO>pC H0:μO≤μCH0:μO≤μC H1:μO>μCH1:μO>μC H0:μO=μCH0:μO=μC H1:μO≠μCH1:μO≠μC H0:μO≥μCH0:μO≥μC H1:μO<μCH1:μO<μC H0:pO=pCH0:pO=pC H1:pO≠pCH1:pO≠pC The test is: right-tailed two-tailed left-tailed The sample consisted of 55 Orange Coast students, with a sample mean GPA of 2.69 and a standard deviation of 0.05, and 55 Coastline students, with a sample mean GPA...
Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.05 significance level. The null and alternative hypothesis would be: H0:pO≥pCH0:pO≥pC H1:pO<pCH1:pO<pC H0:pO≤pCH0:pO≤pC H1:pO>pCH1:pO>pC H0:μO≤μCH0:μO≤μC H1:μO>μCH1:μO>μC H0:μO=μCH0:μO=μC H1:μO≠μCH1:μO≠μC H0:μO≥μCH0:μO≥μC H1:μO<μCH1:μO<μC H0:pO=pCH0:pO=pC H1:pO≠pCH1:pO≠pC The test is: right-tailed two-tailed left-tailed The sample consisted of 55 Orange Coast students, with a sample mean GPA of 2.69 and a standard deviation of 0.05, and 55 Coastline students, with a sample mean GPA...
According to a survey conducted by the Association for Dressings and Sauces, 70% of American adults eat salad once a week. A nutritionist suspects that this percentage is not accurate. She conducts a survey of 234 American adults and finds that 150 of them eat salad once a week. Use a 0.1 significance level to test the claim that the proportion of American adults who eat salad once a week is different from 70%. Hint: When you calculate ˆpp^, round...
Test the claim that the mean GPA of night students is significantly different than the mean GPA of day students at the 0.1 significance level. The null and alternative hypothesis would be: H0:pN≥pDH0:pN≥pD H1:pN<pDH1:pN<pD H0:pN≤pDH0:pN≤pD H1:pN>pDH1:pN>pD H0:μN≥μDH0:μN≥μD H1:μN<μDH1:μN<μD H0:pN=pDH0:pN=pD H1:pN≠pDH1:pN≠pD H0:μN≤μDH0:μN≤μD H1:μN>μDH1:μN>μD H0:μN=μDH0:μN=μD H1:μN≠μDH1:μN≠μD The test is: left-tailed two-tailed right-tailed The sample consisted of 65 night students, with a sample mean GPA of 3.35 and a standard deviation of 0.04, and 65 day students, with a sample mean GPA of...