Question

A point particle-1 with a mass of m is rotating about an axis with an angular...

A point particle-1 with a mass of m is rotating about an axis with an angular velocity of 1 and the distance between the particle-1 and its rotational axis is r. Another point particle-2 with the same mass as particle-1 is rotating about another axis with an angular velocity of 2 and the distance between the particle-2 and its rotational axis is 2r. Both particles have the same rotational kinetic energy. What is the ratio of the angular velocities, 2/1, for these two particles?

A. 8.0 B. 0.50 C. 0.35 D. 0.25 E. 4.0

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
A point particle-1 with a mass of m is rotating about an axis with an angular...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Consider a particle of mass m = 22.0 kg revolving around an axis with angular speed...

    Consider a particle of mass m = 22.0 kg revolving around an axis with angular speed ω. The perpendicular distance from the particle to the axis is r = 0.250 m . The kinetic energy of a rotating body is generally written as K=1/2Iω^2, where I is the moment of inertia (also known as rotational inertia) of the body. Find the moment of inertia of the particle described in the problem introduction with respect to the axis about which it...

  • Consider a particle of mass m = 17.0 kg revolving around an axis with angular speed...

    Consider a particle of mass m = 17.0 kg revolving around an axis with angular speed ω. The perpendicular distance from the particle to the axis is r = 0.250 mThe kinetic energy of a rotating body is generally written as K=12Iω2, where I is the moment of inertia (also known as rotational inertia) of the body. Find the moment of inertia of the particle described in the problem introduction with respect to the axis about which it is rotating....

  • A moon of mass m orbits around a non-rotating planet of mass M with orbital angular velocity . The moon also rotates about its own axis with angular velocity .

    1. A moon of mass \(m\) orbits around a non-rotating planet of mass \(M\) with orbital angular velocity \(\Omega\). The moon also rotates about its own axis with angular velocity \(\omega\). The axis of rotation of the moon is perpendicular to the plane of the orbit. Let \(I\) be the moment of inertia of the moon about its own axis. You can assume \(m<<M\)so that the center ofmass of the system is at the center of the planet.(a) What is...

  • Consider a particle of mass m = 25.0kg revolving around an axis with angular speed ?....

    Consider a particle of mass m = 25.0kg revolving around an axis with angular speed ?. The perpendicular distance from the particle to the axis is r = 1.50m . Assume w=42.0rad/s . What is the magnitude v of the velocity of the particle in m/s? Now that you have found the velocity of the particle, find its kinetic energy K, and express in Joules.

  • Consider a particle of mass m = 17.0 kg revolving around an axis with angular speed...

    Consider a particle of mass m = 17.0 kg revolving around an axis with angular speed ω. The perpendicular distance from the particle to the axis is r = 0.250 m 2.Assume ω = 13.0 rad/s . What is the magnitude v of the velocity of the particle in m/s? 3. Now that you have found the velocity of the particle, find its kinetic energy K.

  • Consider a particle of mass m = 21.0 kg revolving around an axis with angular speed...

    Consider a particle of mass m = 21.0 kg revolving around an axis with angular speed ω. The perpendicular distance from the particle to the axis is r = 1.75 m . (Figure 1) 1. Assume ω = 21.0 rad/s . What is the magnitude v of the velocity of the particle in m/s? 2. Now that you have found the velocity of the particle, find its kinetic energy K. Express your answer numerically, in joules.

  • : A uniform ring is rotating about vertical axis with angular velocity initially. A point insect...

    : A uniform ring is rotating about vertical axis with angular velocity initially. A point insect (S) having a same mass as that of the ring starts walking from the lowest point P, and finally reaches the point P ( as shown in figure ). If the final angular velocity of the ring is 0/x, find the value of x. axis of rotation 90°

  • Consider a particle of mass mm that is revolving with angular speed ω around an axis....

    Consider a particle of mass mm that is revolving with angular speed ω around an axis. The perpendicular distance from the particle to the axis is rr (Figure 1). Part A: Find the kinetic energy K of the rotating particle. Express your answer in terms of m r ω. part C:Find the moment of inertia IhoopIhoop of a hoop of radius rr and mass mm with respect to an axis perpendicular to the hoop and passing through its center. (Figure...

  • 1. What is the angular momentum of a 0.240-kg ball rotating on the end of a...

    1. What is the angular momentum of a 0.240-kg ball rotating on the end of a thin string in a circle of radius 1.35 m at an angular speed of 15.0 rad/s ? 2. A diver can reduce her moment of inertia by a factor of about 4.0 when changing from the straight position to the tuck position. If she makes 2.0 rotations in 1.5 s when in the tuck position, what is her angular speed (rev/s) when in the...

  • Consider a particle of mass m = 25.0 kg revolving around an axis with angular speed ω. The perpendicular distance from...

    Consider a particle of mass m = 25.0 kg revolving around an axis with angular speed ω. The perpendicular distance from the particle to the axis is r= 1.75 m . (Figure 1) Part A Which of the following are units for expressing rotational velocity, commonly denoted by ω? . Check all that apply. radians per second degrees per second meters per second arc seconds revolutions per second Part C Now that you have found the velocity of the particle,...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT