Question

The mean of a list of numbers is its arithmetic average. The median of a list is its middle value when the values are placed in order. For example, if an ordered list contains 1, 2, 3, 4, 5, 6, 10, 11, and 12, then the mean is 6, and their median is 5. Write an application that allows you to enter nine integers and displays the values, their mean, and their median. Correct program

import java.util.Scanner;
import java.util.*;
class MeanMedian

{

public static void main (String[] args)

{

float mean;

int median,sum=0;

int arr[]=new int[9];

Scanner in = new Scanner(System.in); // Reading from System.in
System.out.println("Enter 9 numbers : ");
for(int i=0;i<9;i++)

{

arr[i] = in.nextInt();

sum=sum+arr[i];

}

mean=(float)sum/9;

Arrays.sort(arr);

median=arr[4];

System.out.println("mean = "+mean);
System.out.println("median = "+median);

}

}

Answer 1

import java.util.Scanner;
import java.util.*;
public class MeanMedian {
  
    public static double findMean(int a[], int n)
    {
        int sum = 0;
        for (int i = 0; i < n; i++)
            sum += a[i];
    
        return (double)sum / (double)n;
    }

    // Function for calculating median
    public static double findMedian(int a[], int n)
    {
        // First we sort the array
        Arrays.sort(a);
        // check for even case
        if (n%2!=0)
        return (double)a[n/2];
    
        return (double)(a[(n-1)/2]+a[n/2])/2.0;
    }
  
    public static void main(String args[]) {
        Scanner in=new Scanner(System.in);
        int arr[]=new int[9];
        for(int i=0;i<9;i++)
        {
            arr[i]=in.nextInt();
        }
        int n = arr.length;
        System.out.println("Mean = " + findMean(arr, n));
        System.out.println("Median = " + findMedian(arr, n));
    }
}