The probability of winning on a lot machine is 5%. If a person plays the machine 500 times, find the probability of winning 30 times. Use the normal approximation to the binomial distribution.
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P( Winning) = 0.05 = p
n= 500
Mean = np= 0.05*500 = 25
variance= np(1-p) = 500*0.05*(1-0.05) =23.75
Let X be the number of winning
X~ N( 25, 23.75) [ normal approximation)
P( X = 30 ) = P( X< 30.5) [ using continuity correction]
= P(
<
)
= P( Z < 1.13)
= 0.87076
The probability of winning on a lot machine is 5%. If a person plays the machine...
The probability of winning on a slot machine is 5%. If a person plays the machine 500 times, find the probability of winning at least 30 times. (A) Almost 0 B) Between 0.01 and 0.20 (C) Between 0.20 and 0.40 (D) Between 0.40 and 0.60 (E) Greater than 0.60
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Probability and Statistical Inference with the
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1) Let Y be b(100,p). To test H0:p = 0.09 against
H1:p > 0.09, we reject H0 and accept
H1 if and only if Y<= 5. Determine the significance
level of the test.
Note: Please use Normal...