Look again at the table in Part B, repeated below.
| Solid | Concentration (M) | Strength of light emitted |
| A | 0.20 | Bright |
| B | 0.20 | Dim |
| C | 0.20 | None |
| D | 0.20 | Bright |
The student is told that one of the four solids tested is actually
magnesium bromide,MgBr2. Which of the solids could be MgBr2?
Check all that apply.
Check all that apply.
| A |
| B |
| C |
| D |
Solution::
The correct options are a and d.
MgBr2 is an ionic compound and also a strong electrolyte.
MgBr2 (aq) = Mg2+ (aq) + 2Br- (aq)
Therefore its conductivity is very high due to the presence of Mg2+ and Br- ions. Thus, light is bright.
Look again at the table in Part B, repeated below. Solid Concentration (M) Strength of light...
Look again at the table in Part B, repeated below. Solid Concentration (M) Strength of light emitted A 0.20 Bright B 0.20 Dim C 0.20 None D 0.20 Bright The student is told that one of the four solids tested is actually magnesium bromide,MgBr2. Which of the solids could be MgBr2? Check all that apply. Check all that apply. A B C D
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