A chunk of magnesium weighing 19.4 grams and originally at 97.43 °C is dropped into an...
A chunk of magnesium weighing
19.4 grams and originally at
97.43 °C is dropped into an insulated cup
containing 80.9 grams of water at
23.10 °C.
Assuming that all of the heat is transferred to the water, the
final temperature of the water is °C.
Homework Answers
Answer
Heat lost by magnesium = Heat gained by water
mass of Magnesium *specific feat of magnesium* temperature change = mass of water**specific feat of water* temperature change
19.4 grams*1.02 J/gC* (97.43- Tf)= 80.9 grams*4.184 J/gC*(Tf-23.10)
19.788*(97.43- Tf) = 338.48 *(Tf-23.10)
1927.94-19.788Tf = 338.48Tf- 7818.88
1927.94+7818.88 = 338.48Tf+19.788Tf
9746.828 =358.268Tf
Tf =9746.828/358.268
Tf = 27.2 degree C
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