Question

Part I: Pseudocode

The first part of this assignment is to create pseudocode that reflects the main elements of the logic that will drive the code. This section should not be produced using actual code. However, you should include important variables, calculations, relationships, and/or any critical components of the problem. Using the How to Write Pseudocode document for guidance, address the following:

A. Analyze the given problem statement.

B. Break the problem down into distinct steps of pseudocode that will solve the problem.

C. Create variables to track the various elements in the pseudocode.

D. If applicable, determine any breakdown of pseudocode into functions and/or classes.

E. Use natural language to work through the problems.

Imagine that you are a student about to graduate. You realize that it would be handy to have a tool to help you calculate your GPA and determine whether you are graduating with honors. In the GPA scale, an A is a 4.0, a B is 3.0, a C is 2.0, a D is 1.0, and an F is 0.0. GPA scales typically factor in course credits as well, but all of your classes are the same number of credits, so you can ignore that as a variable.

Honor level is based on the following scale: greater than or equal to 3.9 is summa cumlaude, 3.8 to 3.89 is magna cumlaude, 3.65 to 3.79 is cumlaude, below 3.65 there are no honors given.

Your graduation calculator should prompt the user to input four grades as the numerical value (you can ask four times, one at a time), calculate the average of the inputted grades, display this value to the user, and display a Boolean (true or false) statement for each of the honor levels.

You can use the grades A, A, B, and A as a test case, which should result in the following: Your GPA is 3.75.

Graduating summa cumlaude is false.

Graduating magna cumlaude is false.

Graduating cumlaude is true.

Graduating without honors is false.

Answer 1

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PSEDOCODE

char a,b,c,d;

output("Enter Grades")

input(a,b,c,d);

float E,X,Y,Z;

if(a == 'A')

E=4.0

else if(a=='B')

E = 3.0

else if(a == 'C')

E = 2.0

else if(a == 'D')

E=1.0

else if(a == F)

E=0;

else No found

for all a,b,c,d

int s

s = E+X+Y+Z/4

Now just compare the result of s with all values points

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C++ CODE

=============================================================================================

#include<iostream>

using namespace std;

int main(){

char a,b,c,d;

bool l1,l2,l3,l4;// for true or false

cout << "Enter values of grades";

cin >> a >> b >> c >> d; //input

float e,x,y,z,sum;

if(a =='A') e = 4.0;

else if(a == 'B') e = 3.0; //for all values to be print

else if(a == 'C') e = 2.0;

else if(a == 'D') e = 1.0;

else if(a == 'F') e = 0;

else cout << "Wrong Grade";

if(b =='A') x = 4.0;

else if(b == 'B') x = 3.0;

else if(b == 'C') x = 2.0;

else if(b == 'D') x = 1.0;

else if(b == 'F') x = 0;

else cout << "Wrong Grade";

if(c =='A') y = 4.0;

else if(c == 'B') y = 3.0;

else if(c == 'C') y = 2.0;

else if(c == 'D') y = 1.0;

else if(c == 'F') y = 0;

else cout << "Wrong Grade";

if(d =='A') z = 4.0;

else if(d == 'B') z = 3.0;

else if(d == 'C') z = 2.0;

else if(d == 'D') z = 1.0;

else if(d == 'F') z = 0;

else cout << "Wrong Grade";

sum = (e+x+y+z)/4;

if(sum >= 3.9) l1 = true;

else if(sum <=3.89 && sum >=3.8) l2 = true;

else if(sum >=3.65 && sum <=3.79) l3 = true;

else if(sum <=3.65) l4 = true;

cout << "Average is" << sum<<endl;

cout << "Graduating summa cumlaude is" << l1<<endl;

cout << "Graduating magna cumlaude is" << l2<<endl;

cout << "Graduating cumlaude is"<< l3 << endl;

cout << "Graduating without honors is" << l4<< endl;

return 0;

}

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