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A college student stands on a balcony of a sorority house a distance of 10.0 meters...

A college student stands on a balcony of a sorority house a distance of 10.0 meters above the ground. Her sorority sister is on the ground below the balcony, and tosses her keys straight upward toward her friend who catches the keys 2.7 seconds later. With what speed were the keys initially thrown?

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Answer #1

Solution)

Given, distance, S=10 m

Time, t=2.7 secs

Speed, v=?

We know, S=ut-0.5 gt^2

10 m=u*2.7 -0.5*9.8*2.7^2

So, initial velocity, u=16.93 m/s

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