Benzoic acid, C6H5COOH, is a weak acid (Ka = 6.28 * 10^-5). if i dissolve 1.22g of it in enough water to make 500mL of solution what is the resulting pH of the solution?
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Benzoic acid, C6H5COOH, is a weak acid (Ka = 6.28 * 10^-5). if i dissolve 1.22g...
ka for benzoic acid is 6.28 x 10-5. Calculate pH of a solution resulting from dissolving 0.01 mols of benzoic acid. C6H5COOH and 0.5 mol of sodium benzoate in 10L of solution. You are allowed to use negligible values for any x values since ka is low.
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