Suppose Cameroon beats China 5 to 2 in Soccer.
(a) What’s the conditional probability that Cameroon was always ahead.
(b) What’s the probability that Cameroon scored the first two goals?
(c) What’s the conditional probability that Cameroon was always ahead (from the opening goal) given that Cameroon scored the first two goals?
a)
this is problem based on Bertrand's ballot theorem
p = 5 and q = 2
required probability = (p-q)/(p+q) = 3/7
b)
W - scored by Cameroon
L - scored by china
total number of ways to arrange 5 W and 2L = 7!/(5! *2!) = 21
number of ways to arrange when first two are WW = 5C2 = 10
hence required probability = 10/21
Suppose Cameroon beats China 5 to 2 in Soccer. (a) What’s the conditional probability that Cameroon...
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Cases in Probability
Conditional Events - Coins & Jars
Suppose there are two
jars, A and B. Jar A contains 4 red and 3 blue
balls. Jar B contains 2 red and 5 blue
balls.
Flip a coin twice and select Jar A on 2 heads.
Otherwise select Jar B. Next, draw [randomly] one
ball from the selected jar.
What is the probability of getting a red ball
Given a red ball was selected, what is the probability
that it...