9) The free energy change is calculated:
ΔG = - R * T * ln K = - 0.008314 * 401 K * ln (2.59) = - 3.18 kJ / mol
10) The moles of the buffer components are calculated:
n Acid = g / MM = 0.55 / 112 = 0.005 mol
n Salt = 0.65 / 134 = 0.005 mol
The pH = pKa = 4.19
11) The molar ratio of the buffer components is calculated:
n Salt / n Acid = 10 ^ (pH - pKa) = 10 ^ (10.2 - 10.4) = 0.6
It has:
i) n Salt - 0.6 * n Acid = 0
ii) n Salt + n Acid = M * V = 0.125 M * 0.8 L = 0.1 mol
The system of equations is solved:
n Salt = 0.04 mol
n Acid = 0.06 mol
A CAPSO mass of:
m CAPSO = n * MM = 0.1 mol * 237.32 g / mol = 2.37 g
0.1 M NaOH is added a volume of:
V NaOH = n * 1000 / M = 0.04 * 1000 / 0.1 = 400 mL
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**ACID BASE TABLE** ->
refer to table for values
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